## Proof Exercise #1 Continuation 8

Yes.

Therefore:

choice #1: v is a divisor of 29.

choice #2: v^2 is a divisor of 29.

choice #3: 29 is a divisor of v.

choice #4: There exists a member k of Z such that k = 1/2.

choice #5: 2 is a divisor of v.

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Therefore:

choice #1: v is a divisor of 29.

choice #2: v^2 is a divisor of 29.

choice #3: 29 is a divisor of v.

choice #4: There exists a member k of Z such that k = 1/2.

choice #5: 2 is a divisor of v.

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